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50+6x=x^2
We move all terms to the left:
50+6x-(x^2)=0
determiningTheFunctionDomain -x^2+6x+50=0
We add all the numbers together, and all the variables
-1x^2+6x+50=0
a = -1; b = 6; c = +50;
Δ = b2-4ac
Δ = 62-4·(-1)·50
Δ = 236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{236}=\sqrt{4*59}=\sqrt{4}*\sqrt{59}=2\sqrt{59}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{59}}{2*-1}=\frac{-6-2\sqrt{59}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{59}}{2*-1}=\frac{-6+2\sqrt{59}}{-2} $
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